Landing: zeta ball video, new cut with the tip–halve–shift scene
Co-Authored-By: Claude Fable 5.1 <noreply@anthropic.com> Claude-Session: https://claude.ai/code/session_01FAqjv3n4yABxvJPJHFRhVA
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@@ -54,8 +54,8 @@ a.card p{margin:0;color:var(--muted);font-size:12.5px}
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<p class="lede">Force up–down mirror symmetry on the yantra while keeping all 29 triple points exact, and two of its bases are pulled into one line, carrying one point on the axis and a mirror pair: 1 + 2.</p>
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<video controls playsinline preload="none" src="https://teahub.xyz/maths/videos/raw/commit/a7601b040a95725e40e58f6ac214a2fe096a3a3e/yantra-symmetry.mp4"></video>
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<h2 style="font-family:var(--display);font-weight:500;font-size:28px;margin:8px 0 0">From Riemann to ζ</h2>
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<p class="lede">The plane is a ball with a lamp on top. Feed ζ a grid and it draws latitude and longitude of a globe lying on its side, poles over 0 and 1. The equator casts the critical line; its two ends are ½ and ∞; the functional equation is the half-turn that swaps the poles and keeps the equator. The Riemann hypothesis, on the ball: every zero lives on the equator, climbing toward the lamp.</p>
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<video controls playsinline preload="none" src="https://teahub.xyz/maths/videos/raw/commit/09ce27644482fc035c25a2fb3861b8e9dd164c45/zeta-ball.mp4"></video>
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<p class="lede">The plane is a ball with a lamp on top. Feed ζ a grid and it draws latitude and longitude of a globe lying on its side: the usual stereographic picture tipped a quarter turn, halved, and slid by ½, so the poles land on 0 and 1. The equator casts the critical line; its two ends are ½ and ∞; the functional equation is the half-turn that swaps the poles and keeps the equator. The Riemann hypothesis, on the ball: every zero lives on the equator, climbing toward the lamp.</p>
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<video controls playsinline preload="none" src="https://teahub.xyz/maths/videos/raw/commit/4c7ac00ce465abf403b9caf270e14bc1b8688a53/zeta-ball.mp4"></video>
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<p class="lede">The same ball in two explorers: put ½ at the centre and the critical line becomes the strut through 0 and ∞, the functional equation a sign flip through the centre. Swap ζ for a function with the same symmetry and no Euler product (Davenport–Heilbronn) and the zeros step off the strut: symmetry alone does not pin them, the arithmetic is the extra incidence.</p>
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<div class="cards">
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<a class="card" href="strut/">
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